Answer
$F=G\frac{mM}{r^{2}}$
At the equator earth radius is more, hence F is less.
So one would weigh slightly less than normal at the equator.
Work Step by Step
$F=G\frac{mM}{r^{2}}$
At the equator earth radius is more, hence F is less.
So one would weigh slightly less than normal at the equator.
