Answer
A
Work Step by Step
Whenever aluminum 28 decays, it should form an antineutrino because it is $\beta-$ decay. Thus it will form silicon-28, an antineutrino, and an electron.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 30 - Nuclear Reactions and Elementary Particles - Learning Path Questions and Exercises - Multiple Choice Questions - Page 1028: 11
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