Answer
a). $(1)$ increase
b). $1.92mm$
c). $2.4mm$
Work Step by Step
a). (1) increase
as $\Delta y=\frac{Lv}{d}$, $v$ being the wavelength
the distance between the maxima would decrease if the distance between the slits was increased.
b). Now, $y_{n}=\frac{nLv}{d}$, n=1
$y=\frac{1\times 3\times 640\times 10^{-9}}{10^{-3}}=1.92mm$
c). $y_{n}=\frac{nLv}{d}$, n=1
$y=\frac{3\times 640\times 10^{-9}}{0.8\times10^{-3}}=2.4mm$