Answer
$66.7$%
Work Step by Step
From Exercise 25, apparent depth $d^{'}=\frac{d}{n}$
where d is the actual depth.
So, required percentage $=\frac{\frac{d}{n}}{d}\times100=\frac{100}{n}$
For oil , n=1.5
Hence. required percentage $=\frac{100}{1.5}=66.7$%