Answer
$1.2A$
Work Step by Step
$P_{avg}=i_{RMS}\times V_{RMS}$
i.e. $P_{avg}=R(i_{RMS})^{2}$
Now, average power = $15W$, $R=10Ohm$
Thus, $i_{RMS}=\sqrt \frac{15}{10}=1.2A$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 21 - AC Circuits - Learning Path Questions and Exercises - Exercises - Page 748: 3
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