Answer
(a) coulomb/volt
Work Step by Step
Capacitance $C=\frac{Charge\,q}{Potential\,difference\,V}$
Therefore S.I unit of capacitance F$=\frac{S.I\,unit\,of\,q}{S.I\,unit\,of\,V}=\frac{coulomb}{volt}$.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Multiple Choice Questions - Page 590: 15
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