Answer
$4.8\times10^{-5}J$
Work Step by Step
$V=12V$
$q=-4.0\times10^{-6}C$
Work done = Potential difference $\times$ charge
= $12\times (-4) \times 10^{-6}J$
= $4.8\times10^{-5}J$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 591: 2
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