Answer
If the capacitances are $C_{1}$ and $C_{2}$,
a) Maximum equivalent capacitance is attained when they are in parallel, i.e. $C_{1}+C_{2}$.
b) Minimum capacitance is attained when they are in series, i.e. $\frac{C_{1}C_{2}}{C_{1}+C_{2}}$.
Work Step by Step
If the capacitances are $C_{1}$ and $C_{2}$,
a) Maximum equivalent capacitance is attained when they are in parallel, i.e. $C_{1}+C_{2}$.
b) Minimum capacitance is attained when they are in series, i.e. $\frac{C_{1}C_{2}}{C_{1}+C_{2}}$.