Answer
(d) $\frac{kA^{2}}{2}$
Work Step by Step
The total energy of a mass spring system in simple harmonic motion is :-
$E=\frac{kA^{2}}{2}$
where A is the amplitude of motion.
This E is the sum of KE and PE.
So the maximum value of kinetic energy is equal to $\frac{kA^{2}}{2}$ and it occurs at equilibrium position where potential energy is zero.
