College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 384: 36

Answer

(a) $-0.54mm$ (b) $0.3mm$

Work Step by Step

(a) We know that $\Delta L=L\alpha \Delta T$ We plug in the known values to obtain: $\Delta L=12\times 10^{-6}(-45)$ This simplifies to: $\Delta L=-0.54mm$ (b) As $\Delta L=L\alpha \Delta T$ We plug in the known values to obtain: $\Delta L=12\times 10^{-6} \times 25$ This simplifies to: $\Delta L= 0.3mm$
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