Answer
(c) $\mu L$
Work Step by Step
$1\,in^{3}=0.0163871\,L$
$1\,mL=0.001\,L$
$1\,\mu L=10^{-6}\,L$
$1\,cm^{3}=0.001\,L$
$1\,\mu L\lt 1\,mL=1\,cm^{3}\lt1\,in^{3}$
The largest number is used with the smallest unit and in this case, the smallest unit of volume is $\mu L$.