Answer
The fundamental frequency of the string is $17,300~Hz$
Work Step by Step
We can find the wave speed along the string:
$v = \sqrt{\frac{Y}{\rho}}$
$v = \sqrt{\frac{9.0\times 10^{10}~Pa}{8500~kg/m^3}}$
$v = 3254~m/s$
We can find the fundamental frequency:
$f = \frac{v}{\lambda}$
$f = \frac{v}{2L}$
$f = \frac{3254~m/s}{(2)(0.094~m)}$
$f = 17,300~Hz$
The fundamental frequency of the string is $17,300~Hz$.
