Answer
The correct answer is:
C. $2\times 10^3~N/m^2$
Work Step by Step
We can find the gauge pressure difference for a depth of 20 cm in the water:
$\Delta P_g = \rho~g~\Delta h$
$\Delta P_g = (1000~kg/m^3)(10~m/s^2)(0.20~m)$
$\Delta P_g = 2000~Pa$
The correct answer is:
C. $2\times 10^3~N/m^2$
