Answer
The initial speed of the plate should be $2.76~m/s$
Work Step by Step
We can find the rate of deceleration of the plate is it slides:
$mg~\mu_k = ma$
$a = g~\mu_k$
$a = (9.80~m/s^2)(0.32)$
$a = 3.136~m/s^2$
Note that the plate's acceleration as it slides is $-3.136~m/s^2$. We can find the initial speed:
$v_f^2 = v_0^2+2ax$
$v_0^2 = v_f^2-2ax$
$v_0 = \sqrt{v_f^2-2ax}$
$v_0 = \sqrt{0-(2)(-3.136~m/s^2)(0.44~m)}$
$v_0 = 2.76~m/s$
The initial speed of the plate should be $2.76~m/s$
