Answer
(a) $2.21\times 10^5~Pa$
(b) $1650~torr$
(c) $2.18~atm$
Work Step by Step
(a) We can convert $32~lb/in^2$ to units of Pa:
$32~lb/in^2 \times \frac{6895~Pa}{1~lb/in^2} = 2.21\times 10^5~Pa$
(b) We can convert $32~lb/in^2$ to units of torr:
$32~lb/in^2 \times \frac{51.7~torr}{1~lb/in^2} = 1650~torr$
(c) We can convert $32~lb/in^2$ to units of atm:
$32~lb/in^2 \times \frac{1~atm}{14.7~lb/in^2} = 2.18~atm$
