Answer
$L = 0.19~kg~m^2/s$
Work Step by Step
We can express the angular speed in units of rad/s:
$3.0~rev/s \times \frac{2\pi~rad}{1~rev} = 18.85~rad/s$
We can find the angular momentum:
$L = I~\omega$
$L = \frac{1}{2}MR^2~\omega$
$L = \frac{1}{2}(2.0~kg)(0.10~m)^2~(18.85~rad/s)$
$L = 0.19~kg~m^2/s$
