Answer
The angular momentum is $~0.0864~kg~m^2/s$
Work Step by Step
We can express the angular speed in units of rad/s:
$0.550~rev/s\times \frac{2\pi~rad}{1~rev} = 3.456~rad/s$
We can find the angular momentum:
$L = I~\omega$
$L = \frac{1}{2}MR^2~\omega$
$L = \frac{1}{2}(5.00~kg)(0.100~m)^2~(3.456~rad/s)$
$L = 0.0864~kg~m^2/s$
The angular momentum is $~0.0864~kg~m^2/s$.
