Answer
(a) $\tau = 58.5~N\cdot m$
(b) $\tau = 39.9~N\cdot m$
(c) $\tau = 0$
Work Step by Step
The magnitude of the torque can be expressed as $\tau = r~F~sin~\theta$, where $r$ is the displacement between the rotation axis and the point where the force is applied, $F$ is the force, and $\theta$ is the angle between the force vector and the displacement vector $r$.
We can find the magnitude of the torque for each situation:
(a) $\tau = r~ F~sin~\theta$
$\tau = (1.26~m)(46.4~N)~sin~90^{\circ}$
$\tau = 58.5~N\cdot m$
(b) $\tau = r~ F~sin~\theta$
$\tau = (1.26~m)(46.4~N)~sin~43.0^{\circ}$
$\tau = 39.9~N\cdot m$
(c) $\tau = r~ F~sin~\theta$
$\tau = (1.26~m)(46.4~N)~sin~0^{\circ}$
$\tau = 0$
