Answer
The magnitude of the torque that the cord applies to the drum is $~4.5~N\cdot m$
Work Step by Step
The torque is $\tau = r\times F$, where $r$ is the smallest distance between the force vector and the rotation axis, and $F$ is the perpendicular component of the force vector.
We can find the magnitude of the torque:
$\tau = r\times F$
$\tau = (0.060~m)(75~N)$
$\tau = 4.5~N\cdot m$
The magnitude of the torque that the cord applies to the drum is $~4.5~N\cdot m$
