Answer
The rotational inertia of the disk is $0.98~kg~m^2$
Work Step by Step
We can find the rotational inertia of the disk:
$I = \frac{1}{2}MR^2 = \frac{1}{2}(49~kg)(0.20~m)^2 = 0.98~kg~m^2$
The rotational inertia of the disk is $0.98~kg~m^2$.
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 8 - Problems - Page 310: 2
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