Answer
The total momentum of the ship and the crew is $~5.0\times 10^9~kg~m/s$
Work Step by Step
We can find the magnitude of the total momentum of the ship and the crew:
$p = m~v$
$p = (2.0\times 10^3~kg+4.8\times 10^4~kg)~(1.0\times 10^5~m/s)$
$p = (5.0\times 10^4~kg)~(1.0\times 10^5~m/s)$
$p = 5.0\times 10^9~kg~m/s$
The total momentum of the ship and the crew is $~5.0\times 10^9~kg~m/s$.
