College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 228: 21

Answer

The gravitational potential energy of Sean and the parachute at the top of the tower is $54,840~J$

Work Step by Step

We can find the gravitational potential energy at the top of the tower: $U_g = mgh$ $U_g = (68.0~kg)(9.80~m/s^2)(82.3~m)$ $U_g = 54,840~J$ The gravitational potential energy of Sean and the parachute at the top of the tower is $54,840~J$.
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