Answer
The radial acceleration of an African baobab tree located at the equator is $3.37\times 10^{-2}~m/s^2$
Work Step by Step
Let $~~r = 6.38\times 10^6~m$
We can find the angular speed of the earth as it rotates:
$\omega = \frac{\Delta \theta}{\Delta t}$
$\omega = \frac{2\pi~rad}{(24)\cdot (3600~s)}$
$\omega = 7.27\times 10^{-5}~rad/s$
We can find the radial acceleration of an African baobab tree located at the equator:
$a_c = \omega^2~r$
$a_c = (7.27\times 10^{-5}~rad/s)^2~(6.38\times 10^6~m)$
$a_c = 3.37\times 10^{-2}~m/s^2$
The radial acceleration of an African baobab tree located at the equator is $3.37\times 10^{-2}~m/s^2$.
