Answer
The penny hits the ground with a velocity of $85.0~m/s$
Work Step by Step
We can find the velocity $v_f$ when the penny hits the ground:
$v_f^2 = v_0^2+2a\Delta y$
$v_f = \sqrt{v_0^2+2a\Delta y}$
$v_f = \sqrt{0+(2)(9.80~m/s^2)(369~m)}$
$v_f = 85.0~m/s$
The penny hits the ground with a velocity of $85.0~m/s$
