Answer
Since the train requires a distance of 236 meters to stop, and the truck is only 184 meters ahead, the train can not be stopped in time.
Work Step by Step
We can find the rate of deceleration:
$F = ma$
$a = \frac{F}{m}$
$a = \frac{84,000~N}{55,200~kg}$
$a = 1.52~m/s^2$
We can find the required distance for the train to stop:
$v_f^2 = v_0^2+2a\Delta x$
$\Delta x = \frac{v_f^2-v_0^2}{2a}$
$\Delta x = \frac{0-(26.8~m/s)^2}{(2)(-1.52~m/s^2)}$
$\Delta x = 236~m$
Since the train requires a distance of 236 meters to stop, and the truck is only 184 meters ahead, the train can not be stopped in time.
