Answer
The correct answer is:
(b) less than $m_2~g$
Work Step by Step
The correct answer is:
(b) less than $m_2~g$
We can consider the motion of block $m_1$:
$T = m_1~a$
$a = \frac{T}{m_1}$
We can consider the motion of block $m_2$:
$m_2~g-T = m_2~a$
$m_2~g-T = m_2~(\frac{T}{m_1})$
$m_1~m_2~g-m_1~T = m_2~T$
$T = \frac{m_1~m_2~g}{m_1+m_2}$
$T = (\frac{m_1}{m_1+m_2})~m_2~g \lt m_2~g$
