Answer
The binding energy is $2.22~MeV$
Work Step by Step
The mass of a deuteron is $2.013553~u$
We can find the mass of one neutron and one proton:
$M = (1.008665~u)+(1.007276~u)$
$M = 2.015941~u$
We can find the missing mass:
$\Delta m = 2.015941~u-2.013553~u$
$\Delta m = 0.002388~u$
We can assume that the energy of the missing mass is the binding energy:
$E = \Delta m~c^2$
$E = (0.002388~u)~c^2$
$E = (0.002388~u)(\frac{931.5~MeV/c^2}{1~u})~c^2$
$E = 2.22~MeV$
The binding energy is $2.22~MeV$
