Answer
$r = 5.7\times 10^{-15}~m$
$V = 7.80\times 10^{-43}~m^3$
Work Step by Step
The nucleus of an $^{107}_{43}Tc$ atom has 107 nucleons.
We can find the radius of the nucleus:
$r = (1.2\times 10^{-15}~m)~A^{1/3}$
$r = (1.2\times 10^{-15}~m)~(107)^{1/3}$
$r = 5.7\times 10^{-15}~m$
We can find the volume of the nucleus:
$V = \frac{4}{3}~\pi~r^3$
$V = \frac{4}{3}~\pi~(5.7\times 10^{-15}~m)^3$
$V = 7.80\times 10^{-43}~m^3$
