Answer
$v = 1420~m/s$
Work Step by Step
We can find the required speed:
$\lambda = \frac{h}{mv}$
$v = \frac{h}{m~\lambda}$
$v = \frac{6.626\times 10^{-34}~J~s}{(1.67\times 10^{-27}~kg)(0.28\times 10^{-9}~m)}$
$v = 1420~m/s$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 28 - Problems - Page 1074: 6
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