Answer
The difference in energy between two helium levels is $2.11~eV$
Work Step by Step
We can find the energy associated with this wavelength:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{587.6\times 10^{-9}~m}$
$E = (3.383\times 10^{-19}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$
$E = 2.11~eV$
The difference in energy between two helium levels is $2.11~eV$.
