Answer
$E = -0.85~eV$
Work Step by Step
We can find the energy of the hydrogen atom in the stationary state $n=4$:
$E = \frac{-E_0}{n^2}$
$E = \frac{-13.6~eV}{4^2}$
$E = -0.85~eV$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 27 - Problems - Page 1042: 33
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