Answer
$E = 2.84\times 10^{-19}~J$
Work Step by Step
We can find the energy of the photon:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{0.701\times 10^{-6}~m}$
$E = 2.84\times 10^{-19}~J$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 27 - Problems - Page 1041: 2
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