Answer
$E = 1326~MeV$
Work Step by Step
We can find the total energy $E$:
$E^2 = E_0^2+(pc)^2$
$E^2 = (939.6~MeV)^2+[(935~MeV/c)(c)]^2$
$E^2 = (939.6~MeV)^2+(935~MeV)^2$
$E^2 = 1757073.16~(MeV)^2$
$E = \sqrt{1757073.16~(MeV)^2}$
$E = 1326~MeV$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 26 - Problems - Page 1013: 75
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