Answer
$E = 0.64~MeV$
Work Step by Step
We can find the total energy:
$E = \gamma~m~c^2$
$E = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}~m~c^2$
$E = \frac{1}{\sqrt{1-\frac{(0.60~c)^2}{c^2}}}~\times (9.1\times 10^{-31}~kg)(3.0\times 10^8~m/s)^2$
$E = (1.25)(9.1\times 10^{-31}~kg)(3.0\times 10^8~m/s)^2$
$E = 1.024\times 10^{-13}~J$
$E = (1.024\times 10^{-13}~J)\times (\frac{1~MeV}{1.60\times 10^{-13}~J})$
$E = 0.64~MeV$
