Answer
(a) The amplitude of the electric field is $7.5~mV/m$
The frequency of the electric field is $3.0~MHz$
(b) The magnitude of the electric field is $4.5~mV/m$
The electric field is directed in the +x-direction.
Work Step by Step
(a) We can find the amplitude of the electric field:
$E = c~B$
$E = (3.0\times 10^8~m/s)~(2.5\times 10^{-11}~T)$
$E = 7.5~mV/m$
The amplitude of the electric field is $7.5~mV/m$
Since the frequency of the electric field is the same as the frequency of the magnetic field, the frequency of the electric field is $3.0~MHz$
(b) We can find the magnitude of the electric field:
$E = c~B$
$E = (3.0\times 10^8~m/s)~(1.5\times 10^{-11}~T)$
$E = 4.5~mV/m$
The magnitude of the electric field is $4.5~mV/m$
The direction of motion of the EM wave is determined by the cross-product $E\times B$. If the magnetic field points in the +z-direction, and the wave is traveling in the -y-direction, then the electric field must be pointing in the +x-direction. Using the right-hand rule, note that $(+x) \times (+z) = -y$
