College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 20 - Problems - Page 793: 8

Answer

$\omega = 390~rad/s$

Work Step by Step

We can find the angular speed as: $emf = \omega~NBA$ $\omega = \frac{emf}{NBA}$ $\omega = \frac{17.0~V}{(80)(0.45~T)(0.020~m)(0.060~m)}$ $\omega = 390~rad/s$
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