Answer
The force exerted on the foot by the tibia is 2980 N
Work Step by Step
Since the foot is in equilibrium, the sum of the three forces equals zero. We can find the force $F_T$ exerted on the foot by the tibia:
$F_N+F_A-F_T = 0$
$F_T = F_N+F_A$
$F_T = (750~N)+(2230~N)$
$F_T = 2980~N$
The force exerted on the foot by the tibia is 2980 N.
