Answer
$B = 5.4\times 10^{-3}~T$
Work Step by Step
We can find the magnetic field in the solenoid:
$B = \frac{\mu~N~I}{L}$
$B = \frac{(4\pi \times 10^{-7}~T~m/A)(244)(4.5~A)}{0.256~m}$
$B = 5.4\times 10^{-3}~T$
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