Answer
The current in the wire is $0.33~A$ and the current flows from right to left in the wire.
Work Step by Step
For the wire to be suspended by the magnetic force, the magnetic force must be equal in magnitude to the weight of the wire.
We can find the current in the wire:
$ILB = mg$
$I = \frac{mg}{L~B}$
$I = \frac{(0.025~kg)(9.80~m/s^2)}{(1.00~m)(0.75~T)}$
$I = 0.33~A$
By the right hand rule, the current must flow from right to left in order for the magnetic force to be directed upward.
The current in the wire is $0.33~A$ and the current flows from right to left in the wire.
