Answer
$F = 2.4 \times 10^{-12}~N$ (directed vertically upward)
Work Step by Step
We can find the magnetic force:
$F = q~v\times B$
$F = (1.6\times 10^{-19}~C)(6.0 \times 10^6~m/s)(2.50~T)$
$F = 2.4 \times 10^{-12}~N$
By the right hand rule, $v \times B$ is directed vertically upward.
