College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Conceptual Questions - Page 750: 8

Answer

The singly charged ion has a path of larger radius by a factor of 2.

Work Step by Step

We can find an expression for the radius of the path: $F = \frac{mv^2}{r}$ $qvB = \frac{mv^2}{r}$ $r = \frac{mv^2}{qvB}$ $r = \frac{mv}{qB}$ We can see that the doubling the charge $q$ will result in a radius that is half the original radius. Therefore, the singly charged ion has a path of larger radius by a factor of 2.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.