Answer
$W = 3.2\times 10^{-17}~J$
Work Step by Step
We can find the work done by the electric field:
$W = -\Delta U$
$W = -q~\Delta V$
$W = -q~(V_2-V_1)$
$W = -(-1.6\times 10^{-19}~C)~[100~V-(-100~V)]$
$W = 3.2\times 10^{-17}~J$
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