College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 658: 97

Answer

$W = 3.2\times 10^{-17}~J$

Work Step by Step

We can find the work done by the electric field: $W = -\Delta U$ $W = -q~\Delta V$ $W = -q~(V_2-V_1)$ $W = -(-1.6\times 10^{-19}~C)~[100~V-(-100~V)]$ $W = 3.2\times 10^{-17}~J$
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