College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 654: 36

Answer

$d = 1.0~cm$

Work Step by Step

We can find the distance between the surfaces: $V = E~d$ $d = \frac{V}{E}$ $d = \frac{1.0~V}{100.0~N/C}$ $d = 0.010~m$ $d = 1.0~cm$
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