Answer
The correct answer is:
(e) $\frac{N \cdot m}{C}$
Work Step by Step
We can write an equation for electric potential around a point charge $q$:
$V = \frac{k~q}{r}$
$k$ is measured in units of $N~m^2/C^2$
$q$ is measured in units of $C$
$r$ is measured in units of $m$
We can find the units for electric potential:
$\frac{(N~m^2/C^2)(C)}{m} = \frac{N~m}{C}$
The correct answer is:
(e) $\frac{N \cdot m}{C}$
