Answer
The magnitude of the electric force exerted on the raindrop is $2.56\times 10^{-12}~N$ and this force is directed downward.
Work Step by Step
We can find the magnitude of the electric force on the raindrop:
$F = E~\vert q \vert$
$F = (2.0\times 10^6~N/C)(8)(1.6\times 10^{-19}~C)$
$F = 2.56\times 10^{-12}~N$
Since the charge on the raindrop is negative, the force exerted on the raindrop is directed downward.
The magnitude of the electric force exerted on the raindrop is $2.56\times 10^{-12}~N$ and this force is directed downward.
