College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 16 - Problems - Page 613: 11

Answer

The charge on each sphere is $~-5.0\times 10^{-7}~C$

Work Step by Step

We can find the magnitude of the charge $q$ on each sphere: $F = \frac{k~q~q}{r^2}$ $q^2 = \frac{F~r^2}{k}$ $q = \sqrt{\frac{F~r^2}{k}}$ $q = \sqrt{\frac{(0.036~N)(0.25~m)^2}{9.0\times 10^9~N~m^2/C^2}}$ $q = 5.0\times 10^{-7}~C$ Since the magnitude of the charge on each sphere is $5.0\times 10^{-7}~C$ and the charge is negative, the charge on each sphere is $~-5.0\times 10^{-7}~C$
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