Answer
$v_{rms} = \sqrt{\frac{3~k~T}{m}}$
Work Step by Step
We can find the rms speed:
$\overline{KE} = \frac{3}{2}~k~T$
$\frac{1}{2}m~v_{rms}^2 = \frac{3}{2}~k~T$
$v_{rms} = \sqrt{\frac{3~k~T}{m}}$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 13 - Problems - Page 500: 78
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