Answer
(a) The temperature change in kelvins is $-6.0~K$
(b) The temperature change in $^{\circ}F$ is $-10.8~^{\circ}F$
Work Step by Step
(a) Let the two temperatures be $C$ and $C-6.0$.
We can convert the two temperatures to kelvins:
$K_1 = C+273.15$
$K_2 = (C-6.0)+273.15 = C+267.15$
We can find the temperature change in kelvins:
$\Delta T = K_2-K_1$
$\Delta T = (C+267.15)- (C+273.15)$
$\Delta T = -6.0~K$
The temperature change in kelvins is $-6.0~K$
(b) Let the two temperatures be $C$ and $C-6.0$.
We can convert the two temperatures to $^{\circ}F$:
$F_1 = \frac{9}{5}C+32$
$F_2 = \frac{9}{5}(C-6.0)+32 = \frac{9}{5}C+21.2$
We can find the temperature change in $^{\circ}F$:
$\Delta T = F_2-F_1$
$\Delta T = (\frac{9}{5}C+21.2)- (\frac{9}{5}C+32)$
$\Delta T = -10.8~^{\circ}F$
The temperature change in $^{\circ}F$ is $-10.8~^{\circ}F$
