Answer
The correct answer is:
(c) the average translational kinetic energy of the gas.
Work Step by Step
We can write an expression for the average kinetic energy:
$\overline{KE} = \frac{3}{2}~\frac{PV}{N}$
$\overline{KE} = \frac{3}{2}~kT$
We can see that the absolute temperature $T$ of an ideal gas is directly proportional to the average translational kinetic energy of the gas.
The correct answer is:
(c) the average translational kinetic energy of the gas.
