College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 11 - Problems - Page 432: 67

Answer

The total mass of the wire is 49.6 grams.

Work Step by Step

We can find the wave speed in the wire: $v = \lambda~f$ $v = 2L~f$ $v = (2)(2.0~m)(27.5~Hz)$ $v = 110~m/s$ We can find the mass of the wire: $v = \sqrt{\frac{F}{m/L}}$ $v = \sqrt{\frac{F~L}{m}}$ $v^2 = \frac{F~L}{m}$ $m = \frac{F~L}{v^2}$ $m = \frac{(300.0~N)(2.0~m)}{(110~m/s)^2}$ $m = 0.0496~kg$ $m = 49.6~g$ The total mass of the wire is 49.6 grams.
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